Three bags, X, Y and Z contained a certain number of erasers. Bag Z contained
14 as many erasers as X and Y combined. There were 96 more erasers in Bag X than in Bag Z. Bag Y contained 164 more erasers than Bag Z. How many erasers were in Bag Y?
| Bag X |
Bag Y |
Bag Z |
Total |
| 4 u |
1 u |
5 u |
| 1 u + 96 |
1 u + 164 |
|
|
The total number of erasers in Bag X and Bag Y is repeated.
1 u + 96 + 1 u + 164 = 4 u
2 u + 260 = 4 u
4 u - 2 u = 260
2 u = 260
1 u = 260 ÷ 2 = 130
Number of erasers in Bag Y
= 1 u + 164
= 1 x 130 + 164
= 294
Answer(s): 294
