Three bags, W, X and Y contained a certain number of cartoon figurines. Bag Y contained
311 as many cartoon figurines as W and X combined. There were 90 more cartoon figurines in Bag W than in Bag Y. Bag X contained 105 more cartoon figurines than Bag Y. How many cartoon figurines were in Bag X?
| Bag W |
Bag X |
Bag Y |
Total |
| 11 u |
3 u |
14 u |
| 3 u + 90 |
3 u + 105 |
|
|
The total number of cartoon figurines in Bag W and Bag X is repeated.
3 u + 90 + 3 u + 105 = 11 u
6 u + 195 = 11 u
11 u - 6 u = 195
5 u = 195
1 u = 195 ÷ 5 = 39
Number of cartoon figurines in Bag X
= 3 u + 105
= 3 x 39 + 105
= 222
Answer(s): 222
