Three packets, G, H and J contained a certain number of coins. Packet J contained
15 as many coins as G and H combined. There were 82 more coins in Packet G than in Packet J. Packet H contained 107 more coins than Packet J. How many coins were in Packet H?
| Packet G |
Packet H |
Packet J |
Total |
| 5 u |
1 u |
6 u |
| 1 u + 82 |
1 u + 107 |
|
|
The total number of coins in Packet G and Packet H is repeated.
1 u + 82 + 1 u + 107 = 5 u
2 u + 189 = 5 u
5 u - 2 u = 189
3 u = 189
1 u = 189 ÷ 3 = 63
Number of coins in Packet H
= 1 u + 107
= 1 x 63 + 107
= 170
Answer(s): 170
