Three bags, P, Q and R contained a certain number of pencils. Bag R contained
15 as many pencils as P and Q combined. There were 96 more pencils in Bag P than in Bag R. Bag Q contained 138 more pencils than Bag R. How many pencils were in Bag Q?
Bag P |
Bag Q |
Bag R |
Total |
5 u |
1 u |
6 u |
1 u + 96 |
1 u + 138 |
|
|
The total number of pencils in Bag P and Bag Q is repeated.
1 u + 96 + 1 u + 138 = 5 u
2 u + 234 = 5 u
5 u - 2 u = 234
3 u = 234
1 u = 234 ÷ 3 = 78
Number of pencils in Bag Q
= 1 u + 138
= 1 x 78 + 138
= 216
Answer(s): 216