Three bags, U, V and W contained a certain number of pens. Bag W contained
411 as many pens as U and V combined. There were 96 more pens in Bag U than in Bag W. Bag V contained 174 more pens than Bag W. How many pens were in Bag V?
Bag U |
Bag V |
Bag W |
Total |
11 u |
4 u |
15 u |
4 u + 96 |
4 u + 174 |
|
|
The total number of pens in Bag U and Bag V is repeated.
4 u + 96 + 4 u + 174 = 11 u
8 u + 270 = 11 u
11 u - 8 u = 270
3 u = 270
1 u = 270 ÷ 3 = 90
Number of pens in Bag V
= 4 u + 174
= 4 x 90 + 174
= 534
Answer(s): 534