Three bags, Q, R and S contained a certain number of pencils. Bag S contained
14 as many pencils as Q and R combined. There were 62 more pencils in Bag Q than in Bag S. Bag R contained 144 more pencils than Bag S. How many pencils were in Bag R?
Bag Q |
Bag R |
Bag S |
Total |
4 u |
1 u |
5 u |
1 u + 62 |
1 u + 144 |
|
|
The total number of pencils in Bag Q and Bag R is repeated.
1 u + 62 + 1 u + 144 = 4 u
2 u + 206 = 4 u
4 u - 2 u = 206
2 u = 206
1 u = 206 ÷ 2 = 103
Number of pencils in Bag R
= 1 u + 144
= 1 x 103 + 144
= 247
Answer(s): 247