Three packets, P, Q and R contained a certain number of erasers. Packet R contained
16 as many erasers as P and Q combined. There were 51 more erasers in Packet P than in Packet R. Packet Q contained 149 more erasers than Packet R. How many erasers were in Packet Q?
Packet P |
Packet Q |
Packet R |
Total |
6 u |
1 u |
7 u |
1 u + 51 |
1 u + 149 |
|
|
The total number of erasers in Packet P and Packet Q is repeated.
1 u + 51 + 1 u + 149 = 6 u
2 u + 200 = 6 u
6 u - 2 u = 200
4 u = 200
1 u = 200 ÷ 4 = 50
Number of erasers in Packet Q
= 1 u + 149
= 1 x 50 + 149
= 199
Answer(s): 199