Three bags, M, N and P contained a certain number of pens. Bag P contained
15 as many pens as M and N combined. There were 97 more pens in Bag M than in Bag P. Bag N contained 200 more pens than Bag P. How many pens were in Bag N?
Bag M |
Bag N |
Bag P |
Total |
5 u |
1 u |
6 u |
1 u + 97 |
1 u + 200 |
|
|
The total number of pens in Bag M and Bag N is repeated.
1 u + 97 + 1 u + 200 = 5 u
2 u + 297 = 5 u
5 u - 2 u = 297
3 u = 297
1 u = 297 ÷ 3 = 99
Number of pens in Bag N
= 1 u + 200
= 1 x 99 + 200
= 299
Answer(s): 299