Three bags, R, S and T contained a certain number of pencils. Bag T contained
15 as many pencils as R and S combined. There were 58 more pencils in Bag R than in Bag T. Bag S contained 149 more pencils than Bag T. How many pencils were in Bag S?
Bag R |
Bag S |
Bag T |
Total |
5 u |
1 u |
6 u |
1 u + 58 |
1 u + 149 |
|
|
The total number of pencils in Bag R and Bag S is repeated.
1 u + 58 + 1 u + 149 = 5 u
2 u + 207 = 5 u
5 u - 2 u = 207
3 u = 207
1 u = 207 ÷ 3 = 69
Number of pencils in Bag S
= 1 u + 149
= 1 x 69 + 149
= 218
Answer(s): 218