Three bags, M, N and P contained a certain number of seashells. Bag P contained
112 as many seashells as M and N combined. There were 98 more seashells in Bag M than in Bag P. Bag N contained 172 more seashells than Bag P. How many seashells were in Bag N?
Bag M |
Bag N |
Bag P |
Total |
12 u |
1 u |
13 u |
1 u + 98 |
1 u + 172 |
|
|
The total number of seashells in Bag M and Bag N is repeated.
1 u + 98 + 1 u + 172 = 12 u
2 u + 270 = 12 u
12 u - 2 u = 270
10 u = 270
1 u = 270 ÷ 10 = 27
Number of seashells in Bag N
= 1 u + 172
= 1 x 27 + 172
= 199
Answer(s): 199