Three bags, V, W and X contained a certain number of buttons. Bag X contained
310 as many buttons as V and W combined. There were 74 more buttons in Bag V than in Bag X. Bag W contained 118 more buttons than Bag X. How many buttons were in Bag W?
Bag V |
Bag W |
Bag X |
Total |
10 u |
3 u |
13 u |
3 u + 74 |
3 u + 118 |
|
|
The total number of buttons in Bag V and Bag W is repeated.
3 u + 74 + 3 u + 118 = 10 u
6 u + 192 = 10 u
10 u - 6 u = 192
4 u = 192
1 u = 192 ÷ 4 = 48
Number of buttons in Bag W
= 3 u + 118
= 3 x 48 + 118
= 262
Answer(s): 262