Three bags, J, K and L contained a certain number of erasers. Bag L contained
14 as many erasers as J and K combined. There were 52 more erasers in Bag J than in Bag L. Bag K contained 188 more erasers than Bag L. How many erasers were in Bag K?
| Bag J |
Bag K |
Bag L |
Total |
| 4 u |
1 u |
5 u |
| 1 u + 52 |
1 u + 188 |
|
|
The total number of erasers in Bag J and Bag K is repeated.
1 u + 52 + 1 u + 188 = 4 u
2 u + 240 = 4 u
4 u - 2 u = 240
2 u = 240
1 u = 240 ÷ 2 = 120
Number of erasers in Bag K
= 1 u + 188
= 1 x 120 + 188
= 308
Answer(s): 308
