Three packets, P, Q and R contained a certain number of cards. Packet R contained
112 as many cards as P and Q combined. There were 65 more cards in Packet P than in Packet R. Packet Q contained 175 more cards than Packet R. How many cards were in Packet Q?
Packet P |
Packet Q |
Packet R |
Total |
12 u |
1 u |
13 u |
1 u + 65 |
1 u + 175 |
|
|
The total number of cards in Packet P and Packet Q is repeated.
1 u + 65 + 1 u + 175 = 12 u
2 u + 240 = 12 u
12 u - 2 u = 240
10 u = 240
1 u = 240 ÷ 10 = 24
Number of cards in Packet Q
= 1 u + 175
= 1 x 24 + 175
= 199
Answer(s): 199