Three bags, A, B and C contained a certain number of postcards. Bag C contained
111 as many postcards as A and B combined. There were 91 more postcards in Bag A than in Bag C. Bag B contained 188 more postcards than Bag C. How many postcards were in Bag B?
Bag A |
Bag B |
Bag C |
Total |
11 u |
1 u |
12 u |
1 u + 91 |
1 u + 188 |
|
|
The total number of postcards in Bag A and Bag B is repeated.
1 u + 91 + 1 u + 188 = 11 u
2 u + 279 = 11 u
11 u - 2 u = 279
9 u = 279
1 u = 279 ÷ 9 = 31
Number of postcards in Bag B
= 1 u + 188
= 1 x 31 + 188
= 219
Answer(s): 219