Three bags, C, D and E contained a certain number of cards. Bag E contained
413 as many cards as C and D combined. There were 54 more cards in Bag C than in Bag E. Bag D contained 116 more cards than Bag E. How many cards were in Bag D?
Bag C |
Bag D |
Bag E |
Total |
13 u |
4 u |
17 u |
4 u + 54 |
4 u + 116 |
|
|
The total number of cards in Bag C and Bag D is repeated.
4 u + 54 + 4 u + 116 = 13 u
8 u + 170 = 13 u
13 u - 8 u = 170
5 u = 170
1 u = 170 ÷ 5 = 34
Number of cards in Bag D
= 4 u + 116
= 4 x 34 + 116
= 252
Answer(s): 252