Three packets, R, S and T contained a certain number of buttons. Packet T contained
110 as many buttons as R and S combined. There were 87 more buttons in Packet R than in Packet T. Packet S contained 193 more buttons than Packet T. How many buttons were in Packet S?
Packet R |
Packet S |
Packet T |
Total |
10 u |
1 u |
11 u |
1 u + 87 |
1 u + 193 |
|
|
The total number of buttons in Packet R and Packet S is repeated.
1 u + 87 + 1 u + 193 = 10 u
2 u + 280 = 10 u
10 u - 2 u = 280
8 u = 280
1 u = 280 ÷ 8 = 35
Number of buttons in Packet S
= 1 u + 193
= 1 x 35 + 193
= 228
Answer(s): 228