Three bags, U, V and W contained a certain number of buttons. Bag W contained
14 as many buttons as U and V combined. There were 95 more buttons in Bag U than in Bag W. Bag V contained 109 more buttons than Bag W. How many buttons were in Bag V?
Bag U |
Bag V |
Bag W |
Total |
4 u |
1 u |
5 u |
1 u + 95 |
1 u + 109 |
|
|
The total number of buttons in Bag U and Bag V is repeated.
1 u + 95 + 1 u + 109 = 4 u
2 u + 204 = 4 u
4 u - 2 u = 204
2 u = 204
1 u = 204 ÷ 2 = 102
Number of buttons in Bag V
= 1 u + 109
= 1 x 102 + 109
= 211
Answer(s): 211