Three packets, G, H and J contained a certain number of coins. Packet J contained
14 as many coins as G and H combined. There were 50 more coins in Packet G than in Packet J. Packet H contained 134 more coins than Packet J. How many coins were in Packet H?
Packet G |
Packet H |
Packet J |
Total |
4 u |
1 u |
5 u |
1 u + 50 |
1 u + 134 |
|
|
The total number of coins in Packet G and Packet H is repeated.
1 u + 50 + 1 u + 134 = 4 u
2 u + 184 = 4 u
4 u - 2 u = 184
2 u = 184
1 u = 184 ÷ 2 = 92
Number of coins in Packet H
= 1 u + 134
= 1 x 92 + 134
= 226
Answer(s): 226