Three packets, Q, R and S contained a certain number of pencils. Packet S contained
111 as many pencils as Q and R combined. There were 89 more pencils in Packet Q than in Packet S. Packet R contained 181 more pencils than Packet S. How many pencils were in Packet R?
Packet Q |
Packet R |
Packet S |
Total |
11 u |
1 u |
12 u |
1 u + 89 |
1 u + 181 |
|
|
The total number of pencils in Packet Q and Packet R is repeated.
1 u + 89 + 1 u + 181 = 11 u
2 u + 270 = 11 u
11 u - 2 u = 270
9 u = 270
1 u = 270 ÷ 9 = 30
Number of pencils in Packet R
= 1 u + 181
= 1 x 30 + 181
= 211
Answer(s): 211