Three bags, L, M and N contained a certain number of pens. Bag N contained
15 as many pens as L and M combined. There were 75 more pens in Bag L than in Bag N. Bag M contained 186 more pens than Bag N. How many pens were in Bag M?
Bag L |
Bag M |
Bag N |
Total |
5 u |
1 u |
6 u |
1 u + 75 |
1 u + 186 |
|
|
The total number of pens in Bag L and Bag M is repeated.
1 u + 75 + 1 u + 186 = 5 u
2 u + 261 = 5 u
5 u - 2 u = 261
3 u = 261
1 u = 261 ÷ 3 = 87
Number of pens in Bag M
= 1 u + 186
= 1 x 87 + 186
= 273
Answer(s): 273