Three packets, L, M and N contained a certain number of cards. Packet N contained
15 as many cards as L and M combined. There were 59 more cards in Packet L than in Packet N. Packet M contained 151 more cards than Packet N. How many cards were in Packet M?
| Packet L |
Packet M |
Packet N |
Total |
| 5 u |
1 u |
6 u |
| 1 u + 59 |
1 u + 151 |
|
|
The total number of cards in Packet L and Packet M is repeated.
1 u + 59 + 1 u + 151 = 5 u
2 u + 210 = 5 u
5 u - 2 u = 210
3 u = 210
1 u = 210 ÷ 3 = 70
Number of cards in Packet M
= 1 u + 151
= 1 x 70 + 151
= 221
Answer(s): 221
