Three bags, K, L and M contained a certain number of pens. Bag M contained
313 as many pens as K and L combined. There were 92 more pens in Bag K than in Bag M. Bag L contained 125 more pens than Bag M. How many pens were in Bag L?
Bag K |
Bag L |
Bag M |
Total |
13 u |
3 u |
16 u |
3 u + 92 |
3 u + 125 |
|
|
The total number of pens in Bag K and Bag L is repeated.
3 u + 92 + 3 u + 125 = 13 u
6 u + 217 = 13 u
13 u - 6 u = 217
7 u = 217
1 u = 217 ÷ 7 = 31
Number of pens in Bag L
= 3 u + 125
= 3 x 31 + 125
= 218
Answer(s): 218