Three packets, Q, R and S contained a certain number of coins. Packet S contained
113 as many coins as Q and R combined. There were 89 more coins in Packet Q than in Packet S. Packet R contained 142 more coins than Packet S. How many coins were in Packet R?
| Packet Q |
Packet R |
Packet S |
Total |
| 13 u |
1 u |
14 u |
| 1 u + 89 |
1 u + 142 |
|
|
The total number of coins in Packet Q and Packet R is repeated.
1 u + 89 + 1 u + 142 = 13 u
2 u + 231 = 13 u
13 u - 2 u = 231
11 u = 231
1 u = 231 ÷ 11 = 21
Number of coins in Packet R
= 1 u + 142
= 1 x 21 + 142
= 163
Answer(s): 163
