Three packets, K, L and M contained a certain number of seashells. Packet M contained
311 as many seashells as K and L combined. There were 57 more seashells in Packet K than in Packet M. Packet L contained 123 more seashells than Packet M. How many seashells were in Packet L?
| Packet K |
Packet L |
Packet M |
Total |
| 11 u |
3 u |
14 u |
| 3 u + 57 |
3 u + 123 |
|
|
The total number of seashells in Packet K and Packet L is repeated.
3 u + 57 + 3 u + 123 = 11 u
6 u + 180 = 11 u
11 u - 6 u = 180
5 u = 180
1 u = 180 ÷ 5 = 36
Number of seashells in Packet L
= 3 u + 123
= 3 x 36 + 123
= 231
Answer(s): 231
