Three packets, A, B and C contained a certain number of cartoon figurines. Packet C contained
411 as many cartoon figurines as A and B combined. There were 96 more cartoon figurines in Packet A than in Packet C. Packet B contained 174 more cartoon figurines than Packet C. How many cartoon figurines were in Packet B?
Packet A |
Packet B |
Packet C |
Total |
11 u |
4 u |
15 u |
4 u + 96 |
4 u + 174 |
|
|
The total number of cartoon figurines in Packet A and Packet B is repeated.
4 u + 96 + 4 u + 174 = 11 u
8 u + 270 = 11 u
11 u - 8 u = 270
3 u = 270
1 u = 270 ÷ 3 = 90
Number of cartoon figurines in Packet B
= 4 u + 174
= 4 x 90 + 174
= 534
Answer(s): 534