Three bags, H, J and K contained a certain number of pencils. Bag K contained
14 as many pencils as H and J combined. There were 69 more pencils in Bag H than in Bag K. Bag J contained 145 more pencils than Bag K. How many pencils were in Bag J?
Bag H |
Bag J |
Bag K |
Total |
4 u |
1 u |
5 u |
1 u + 69 |
1 u + 145 |
|
|
The total number of pencils in Bag H and Bag J is repeated.
1 u + 69 + 1 u + 145 = 4 u
2 u + 214 = 4 u
4 u - 2 u = 214
2 u = 214
1 u = 214 ÷ 2 = 107
Number of pencils in Bag J
= 1 u + 145
= 1 x 107 + 145
= 252
Answer(s): 252