Sabrina, Xylia and Gabby were playing with beads. Sabrina started with 80 beads and in the first game, she won ¹₄ more beads from Xylia. In the second game, Sabrina lost ³₈ of her original number of beads to Gabby. Xylia lost as many beads as Sabrina to Gabby. In the final game, Sabrina won ¹₂ of her original number of beads from Xylia. All of them ended up with the same number of beads.

1. How many beads did Sabrina have in the end?
2. How many beads did Xylia have at first?

	Sabrina	Xylia	Gabby
Before	80
First game	+ 20	- 20
Second game	- 30		+ 30
		- 30	+ 30
Final game	+ 40	- 40
After	1 u	1 u	1 u

(a)
Number of beads that Sabrina won from Xylia
= ¹₄ x 80
= 20

Number of beads that Sabrina lost to Gabby
= ³₈ x 80
= 30

Number of beads that Sabrina won from Xylia
= ¹₂ x 80
= 40

Number of beads that Sabrina had in the end
= 80 + 20 - 30 + 40
= 110

(b)
Number of beads that Xylia had at first
= 1 u + 40 + 30 + 20
= 110 + 40 + 30 + 20
= 200 

Answer(s): (a) 110 ; (b) 200