Yen, Raeann and Jade were playing with beads. Yen started with 56 beads and in the first game, she won ³₄ more beads from Raeann. In the second game, Yen lost ³₈ of her original number of beads to Jade. Raeann lost as many beads as Yen to Jade. In the final game, Yen won ¹₄ of her original number of beads from Raeann. All of them ended up with the same number of beads.

1. How many beads did Yen have in the end?
2. How many beads did Raeann have at first?

	Yen	Raeann	Jade
Before	56
First game	+ 42	- 42
Second game	- 21		+ 21
		- 21	+ 21
Final game	+ 14	- 14
After	1 u	1 u	1 u

(a)
Number of beads that Yen won from Raeann
= ³₄ x 56
= 42

Number of beads that Yen lost to Jade
= ³₈ x 56
= 21

Number of beads that Yen won from Raeann
= ¹₄ x 56
= 14

Number of beads that Yen had in the end
= 56 + 42 - 21 + 14
= 91

(b)
Number of beads that Raeann had at first
= 1 u + 14 + 21 + 42
= 91 + 14 + 21 + 42
= 168 

Answer(s): (a) 91 ; (b) 168