Shannon, Linda and Tammy were playing with beads. Shannon started with 96 beads and in the first game, she won
14 more beads from Linda. In the second game, Shannon lost
18 of her original number of beads to Tammy. Linda lost as many beads as Shannon to Tammy. In the final game, Shannon won
12 of her original number of beads from Linda. All of them ended up with the same number of beads.
- How many beads did Shannon have in the end?
- How many beads did Linda have at first?
|
Shannon |
Linda |
Tammy |
Before |
96 |
|
|
First game |
+ 24 |
- 24 |
|
Second game |
- 12 |
|
+ 12 |
|
|
- 12 |
+ 12 |
Final game |
+ 48 |
- 48 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Shannon won from Linda
=
14 x 96
= 24
Number of beads that Shannon lost to Tammy
=
18 x 96
= 12
Number of beads that Shannon won from Linda
=
12 x 96
= 48
Number of beads that Shannon had in the end
= 96 + 24 - 12 + 48
= 156
(b)
Number of beads that Linda had at first
= 1 u + 48 + 12 + 24
= 156 + 48 + 12 + 24
= 240
Answer(s): (a) 156 ; (b) 240