Abi, Jean and Barbara were playing with beads. Abi started with 40 beads and in the first game, she won ⁴₅ more beads from Jean. In the second game, Abi lost ⁵₈ of her original number of beads to Barbara. Jean lost as many beads as Abi to Barbara. In the final game, Abi won ¹₄ of her original number of beads from Jean. All of them ended up with the same number of beads.

1. How many beads did Abi have in the end?
2. How many beads did Jean have at first?

	Abi	Jean	Barbara
Before	40
First game	+ 32	- 32
Second game	- 25		+ 25
		- 25	+ 25
Final game	+ 10	- 10
After	1 u	1 u	1 u

(a)
Number of beads that Abi won from Jean
= ⁴₅ x 40
= 32

Number of beads that Abi lost to Barbara
= ⁵₈ x 40
= 25

Number of beads that Abi won from Jean
= ¹₄ x 40
= 10

Number of beads that Abi had in the end
= 40 + 32 - 25 + 10
= 57

(b)
Number of beads that Jean had at first
= 1 u + 10 + 25 + 32
= 57 + 10 + 25 + 32
= 124 

Answer(s): (a) 57 ; (b) 124