Cindy, Risa and Jade were playing with beads. Cindy started with 28 beads and in the first game, she won
14 more beads from Risa. In the second game, Cindy lost
67 of her original number of beads to Jade. Risa lost as many beads as Cindy to Jade. In the final game, Cindy won
12 of her original number of beads from Risa. All of them ended up with the same number of beads.
- How many beads did Cindy have in the end?
- How many beads did Risa have at first?
|
Cindy |
Risa |
Jade |
Before |
28 |
|
|
First game |
+ 7 |
- 7 |
|
Second game |
- 24 |
|
+ 24 |
|
|
- 24 |
+ 24 |
Final game |
+ 14 |
- 14 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Cindy won from Risa
=
14 x 28
= 7
Number of beads that Cindy lost to Jade
=
67 x 28
= 24
Number of beads that Cindy won from Risa
=
12 x 28
= 14
Number of beads that Cindy had in the end
= 28 + 7 - 24 + 14
= 25
(b)
Number of beads that Risa had at first
= 1 u + 14 + 24 + 7
= 25 + 14 + 24 + 7
= 70
Answer(s): (a) 25 ; (b) 70