Pamela, Dana and Yoko were playing with beads. Pamela started with 96 beads and in the first game, she won
23 more beads from Dana. In the second game, Pamela lost
18 of her original number of beads to Yoko. Dana lost as many beads as Pamela to Yoko. In the final game, Pamela won
12 of her original number of beads from Dana. All of them ended up with the same number of beads.
- How many beads did Pamela have in the end?
- How many beads did Dana have at first?
|
Pamela |
Dana |
Yoko |
Before |
96 |
|
|
First game |
+ 64 |
- 64 |
|
Second game |
- 12 |
|
+ 12 |
|
|
- 12 |
+ 12 |
Final game |
+ 48 |
- 48 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Pamela won from Dana
=
23 x 96
= 64
Number of beads that Pamela lost to Yoko
=
18 x 96
= 12
Number of beads that Pamela won from Dana
=
12 x 96
= 48
Number of beads that Pamela had in the end
= 96 + 64 - 12 + 48
= 196
(b)
Number of beads that Dana had at first
= 1 u + 48 + 12 + 64
= 196 + 48 + 12 + 64
= 320
Answer(s): (a) 196 ; (b) 320