Abi, Penelope and Cindy were playing with beads. Abi started with 28 beads and in the first game, she won
12 more beads from Penelope. In the second game, Abi lost
27 of her original number of beads to Cindy. Penelope lost as many beads as Abi to Cindy. In the final game, Abi won
14 of her original number of beads from Penelope. All of them ended up with the same number of beads.
- How many beads did Abi have in the end?
- How many beads did Penelope have at first?
|
Abi |
Penelope |
Cindy |
Before |
28 |
|
|
First game |
+ 14 |
- 14 |
|
Second game |
- 8 |
|
+ 8 |
|
|
- 8 |
+ 8 |
Final game |
+ 7 |
- 7 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Abi won from Penelope
=
12 x 28
= 14
Number of beads that Abi lost to Cindy
=
27 x 28
= 8
Number of beads that Abi won from Penelope
=
14 x 28
= 7
Number of beads that Abi had in the end
= 28 + 14 - 8 + 7
= 41
(b)
Number of beads that Penelope had at first
= 1 u + 7 + 8 + 14
= 41 + 7 + 8 + 14
= 70
Answer(s): (a) 41 ; (b) 70