Joelle, Tammy and Kylie were playing with beads. Joelle started with 48 beads and in the first game, she won
14 more beads from Tammy. In the second game, Joelle lost
18 of her original number of beads to Kylie. Tammy lost as many beads as Joelle to Kylie. In the final game, Joelle won
13 of her original number of beads from Tammy. All of them ended up with the same number of beads.
- How many beads did Joelle have in the end?
- How many beads did Tammy have at first?
|
Joelle |
Tammy |
Kylie |
Before |
48 |
|
|
First game |
+ 12 |
- 12 |
|
Second game |
- 6 |
|
+ 6 |
|
|
- 6 |
+ 6 |
Final game |
+ 16 |
- 16 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Joelle won from Tammy
=
14 x 48
= 12
Number of beads that Joelle lost to Kylie
=
18 x 48
= 6
Number of beads that Joelle won from Tammy
=
13 x 48
= 16
Number of beads that Joelle had in the end
= 48 + 12 - 6 + 16
= 70
(b)
Number of beads that Tammy had at first
= 1 u + 16 + 6 + 12
= 70 + 16 + 6 + 12
= 104
Answer(s): (a) 70 ; (b) 104