Tiffany, Jade and Kimberly were playing with beads. Tiffany started with 40 beads and in the first game, she won
12 more beads from Jade. In the second game, Tiffany lost
58 of her original number of beads to Kimberly. Jade lost as many beads as Tiffany to Kimberly. In the final game, Tiffany won
15 of her original number of beads from Jade. All of them ended up with the same number of beads.
- How many beads did Tiffany have in the end?
- How many beads did Jade have at first?
|
Tiffany |
Jade |
Kimberly |
Before |
40 |
|
|
First game |
+ 20 |
- 20 |
|
Second game |
- 25 |
|
+ 25 |
|
|
- 25 |
+ 25 |
Final game |
+ 8 |
- 8 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Tiffany won from Jade
=
12 x 40
= 20
Number of beads that Tiffany lost to Kimberly
=
58 x 40
= 25
Number of beads that Tiffany won from Jade
=
15 x 40
= 8
Number of beads that Tiffany had in the end
= 40 + 20 - 25 + 8
= 43
(b)
Number of beads that Jade had at first
= 1 u + 8 + 25 + 20
= 43 + 8 + 25 + 20
= 96
Answer(s): (a) 43 ; (b) 96