Mary, Shannon and Wendy were playing with beads. Mary started with 40 beads and in the first game, she won
34 more beads from Shannon. In the second game, Mary lost
38 of her original number of beads to Wendy. Shannon lost as many beads as Mary to Wendy. In the final game, Mary won
14 of her original number of beads from Shannon. All of them ended up with the same number of beads.
- How many beads did Mary have in the end?
- How many beads did Shannon have at first?
|
Mary |
Shannon |
Wendy |
Before |
40 |
|
|
First game |
+ 30 |
- 30 |
|
Second game |
- 15 |
|
+ 15 |
|
|
- 15 |
+ 15 |
Final game |
+ 10 |
- 10 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Mary won from Shannon
=
34 x 40
= 30
Number of beads that Mary lost to Wendy
=
38 x 40
= 15
Number of beads that Mary won from Shannon
=
14 x 40
= 10
Number of beads that Mary had in the end
= 40 + 30 - 15 + 10
= 65
(b)
Number of beads that Shannon had at first
= 1 u + 10 + 15 + 30
= 65 + 10 + 15 + 30
= 120
Answer(s): (a) 65 ; (b) 120