Jaslyn, Eva and Kimberly were playing with beads. Jaslyn started with 80 beads and in the first game, she won ²₅ more beads from Eva. In the second game, Jaslyn lost ¹₈ of her original number of beads to Kimberly. Eva lost as many beads as Jaslyn to Kimberly. In the final game, Jaslyn won ¹₅ of her original number of beads from Eva. All of them ended up with the same number of beads.

1. How many beads did Jaslyn have in the end?
2. How many beads did Eva have at first?

	Jaslyn	Eva	Kimberly
Before	80
First game	+ 32	- 32
Second game	- 10		+ 10
		- 10	+ 10
Final game	+ 16	- 16
After	1 u	1 u	1 u

(a)
Number of beads that Jaslyn won from Eva
= ²₅ x 80
= 32

Number of beads that Jaslyn lost to Kimberly
= ¹₈ x 80
= 10

Number of beads that Jaslyn won from Eva
= ¹₅ x 80
= 16

Number of beads that Jaslyn had in the end
= 80 + 32 - 10 + 16
= 118

(b)
Number of beads that Eva had at first
= 1 u + 16 + 10 + 32
= 118 + 16 + 10 + 32
= 176 

Answer(s): (a) 118 ; (b) 176