Nicole, Tiffany and Victoria were playing with beads. Nicole started with 80 beads and in the first game, she won
45 more beads from Tiffany. In the second game, Nicole lost
58 of her original number of beads to Victoria. Tiffany lost as many beads as Nicole to Victoria. In the final game, Nicole won
15 of her original number of beads from Tiffany. All of them ended up with the same number of beads.
- How many beads did Nicole have in the end?
- How many beads did Tiffany have at first?
|
Nicole |
Tiffany |
Victoria |
Before |
80 |
|
|
First game |
+ 64 |
- 64 |
|
Second game |
- 50 |
|
+ 50 |
|
|
- 50 |
+ 50 |
Final game |
+ 16 |
- 16 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Nicole won from Tiffany
=
45 x 80
= 64
Number of beads that Nicole lost to Victoria
=
58 x 80
= 50
Number of beads that Nicole won from Tiffany
=
15 x 80
= 16
Number of beads that Nicole had in the end
= 80 + 64 - 50 + 16
= 110
(b)
Number of beads that Tiffany had at first
= 1 u + 16 + 50 + 64
= 110 + 16 + 50 + 64
= 240
Answer(s): (a) 110 ; (b) 240