Tiffany, Julie and Betty were playing with beads. Tiffany started with 70 beads and in the first game, she won
35 more beads from Julie. In the second game, Tiffany lost
57 of her original number of beads to Betty. Julie lost as many beads as Tiffany to Betty. In the final game, Tiffany won
15 of her original number of beads from Julie. All of them ended up with the same number of beads.
- How many beads did Tiffany have in the end?
- How many beads did Julie have at first?
|
Tiffany |
Julie |
Betty |
Before |
70 |
|
|
First game |
+ 42 |
- 42 |
|
Second game |
- 50 |
|
+ 50 |
|
|
- 50 |
+ 50 |
Final game |
+ 14 |
- 14 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Tiffany won from Julie
=
35 x 70
= 42
Number of beads that Tiffany lost to Betty
=
57 x 70
= 50
Number of beads that Tiffany won from Julie
=
15 x 70
= 14
Number of beads that Tiffany had in the end
= 70 + 42 - 50 + 14
= 76
(b)
Number of beads that Julie had at first
= 1 u + 14 + 50 + 42
= 76 + 14 + 50 + 42
= 182
Answer(s): (a) 76 ; (b) 182