Xuan, Tammy and Jaslyn were playing with beads. Xuan started with 28 beads and in the first game, she won ¹₂ more beads from Tammy. In the second game, Xuan lost ³₇ of her original number of beads to Jaslyn. Tammy lost as many beads as Xuan to Jaslyn. In the final game, Xuan won ¹₄ of her original number of beads from Tammy. All of them ended up with the same number of beads.

1. How many beads did Xuan have in the end?
2. How many beads did Tammy have at first?

	Xuan	Tammy	Jaslyn
Before	28
First game	+ 14	- 14
Second game	- 12		+ 12
		- 12	+ 12
Final game	+ 7	- 7
After	1 u	1 u	1 u

(a)
Number of beads that Xuan won from Tammy
= ¹₂ x 28
= 14

Number of beads that Xuan lost to Jaslyn
= ³₇ x 28
= 12

Number of beads that Xuan won from Tammy
= ¹₄ x 28
= 7

Number of beads that Xuan had in the end
= 28 + 14 - 12 + 7
= 37

(b)
Number of beads that Tammy had at first
= 1 u + 7 + 12 + 14
= 37 + 7 + 12 + 14
= 70 

Answer(s): (a) 37 ; (b) 70