Pamela, Marion and Natalie were playing with beads. Pamela started with 88 beads and in the first game, she won
34 more beads from Marion. In the second game, Pamela lost
18 of her original number of beads to Natalie. Marion lost as many beads as Pamela to Natalie. In the final game, Pamela won
14 of her original number of beads from Marion. All of them ended up with the same number of beads.
- How many beads did Pamela have in the end?
- How many beads did Marion have at first?
|
Pamela |
Marion |
Natalie |
Before |
88 |
|
|
First game |
+ 66 |
- 66 |
|
Second game |
- 11 |
|
+ 11 |
|
|
- 11 |
+ 11 |
Final game |
+ 22 |
- 22 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Pamela won from Marion
=
34 x 88
= 66
Number of beads that Pamela lost to Natalie
=
18 x 88
= 11
Number of beads that Pamela won from Marion
=
14 x 88
= 22
Number of beads that Pamela had in the end
= 88 + 66 - 11 + 22
= 165
(b)
Number of beads that Marion had at first
= 1 u + 22 + 11 + 66
= 165 + 22 + 11 + 66
= 264
Answer(s): (a) 165 ; (b) 264