Dana, Sabrina and Lynn were playing with beads. Dana started with 56 beads and in the first game, she won ³₄ more beads from Sabrina. In the second game, Dana lost ²₇ of her original number of beads to Lynn. Sabrina lost as many beads as Dana to Lynn. In the final game, Dana won ¹₂ of her original number of beads from Sabrina. All of them ended up with the same number of beads.

1. How many beads did Dana have in the end?
2. How many beads did Sabrina have at first?

	Dana	Sabrina	Lynn
Before	56
First game	+ 42	- 42
Second game	- 16		+ 16
		- 16	+ 16
Final game	+ 28	- 28
After	1 u	1 u	1 u

(a)
Number of beads that Dana won from Sabrina
= ³₄ x 56
= 42

Number of beads that Dana lost to Lynn
= ²₇ x 56
= 16

Number of beads that Dana won from Sabrina
= ¹₂ x 56
= 28

Number of beads that Dana had in the end
= 56 + 42 - 16 + 28
= 110

(b)
Number of beads that Sabrina had at first
= 1 u + 28 + 16 + 42
= 110 + 28 + 16 + 42
= 196 

Answer(s): (a) 110 ; (b) 196