Shannon, Min and Hazel were playing with beads. Shannon started with 96 beads and in the first game, she won
14 more beads from Min. In the second game, Shannon lost
18 of her original number of beads to Hazel. Min lost as many beads as Shannon to Hazel. In the final game, Shannon won
13 of her original number of beads from Min. All of them ended up with the same number of beads.
- How many beads did Shannon have in the end?
- How many beads did Min have at first?
|
Shannon |
Min |
Hazel |
Before |
96 |
|
|
First game |
+ 24 |
- 24 |
|
Second game |
- 12 |
|
+ 12 |
|
|
- 12 |
+ 12 |
Final game |
+ 32 |
- 32 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Shannon won from Min
=
14 x 96
= 24
Number of beads that Shannon lost to Hazel
=
18 x 96
= 12
Number of beads that Shannon won from Min
=
13 x 96
= 32
Number of beads that Shannon had in the end
= 96 + 24 - 12 + 32
= 140
(b)
Number of beads that Min had at first
= 1 u + 32 + 12 + 24
= 140 + 32 + 12 + 24
= 208
Answer(s): (a) 140 ; (b) 208