Irene, Min and Gabby were playing with beads. Irene started with 64 beads and in the first game, she won
34 more beads from Min. In the second game, Irene lost
58 of her original number of beads to Gabby. Min lost as many beads as Irene to Gabby. In the final game, Irene won
14 of her original number of beads from Min. All of them ended up with the same number of beads.
- How many beads did Irene have in the end?
- How many beads did Min have at first?
|
Irene |
Min |
Gabby |
Before |
64 |
|
|
First game |
+ 48 |
- 48 |
|
Second game |
- 40 |
|
+ 40 |
|
|
- 40 |
+ 40 |
Final game |
+ 16 |
- 16 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Irene won from Min
=
34 x 64
= 48
Number of beads that Irene lost to Gabby
=
58 x 64
= 40
Number of beads that Irene won from Min
=
14 x 64
= 16
Number of beads that Irene had in the end
= 64 + 48 - 40 + 16
= 88
(b)
Number of beads that Min had at first
= 1 u + 16 + 40 + 48
= 88 + 16 + 40 + 48
= 192
Answer(s): (a) 88 ; (b) 192