Risa, Linda and Irene were playing with beads. Risa started with 70 beads and in the first game, she won
35 more beads from Linda. In the second game, Risa lost
47 of her original number of beads to Irene. Linda lost as many beads as Risa to Irene. In the final game, Risa won
12 of her original number of beads from Linda. All of them ended up with the same number of beads.
- How many beads did Risa have in the end?
- How many beads did Linda have at first?
|
Risa |
Linda |
Irene |
Before |
70 |
|
|
First game |
+ 42 |
- 42 |
|
Second game |
- 40 |
|
+ 40 |
|
|
- 40 |
+ 40 |
Final game |
+ 35 |
- 35 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Risa won from Linda
=
35 x 70
= 42
Number of beads that Risa lost to Irene
=
47 x 70
= 40
Number of beads that Risa won from Linda
=
12 x 70
= 35
Number of beads that Risa had in the end
= 70 + 42 - 40 + 35
= 107
(b)
Number of beads that Linda had at first
= 1 u + 35 + 40 + 42
= 107 + 35 + 40 + 42
= 224
Answer(s): (a) 107 ; (b) 224