Xuan, Betty and Pamela were playing with beads. Xuan started with 56 beads and in the first game, she won ¹₄ more beads from Betty. In the second game, Xuan lost ⁶₇ of her original number of beads to Pamela. Betty lost as many beads as Xuan to Pamela. In the final game, Xuan won ¹₂ of her original number of beads from Betty. All of them ended up with the same number of beads.

1. How many beads did Xuan have in the end?
2. How many beads did Betty have at first?

	Xuan	Betty	Pamela
Before	56
First game	+ 14	- 14
Second game	- 48		+ 48
		- 48	+ 48
Final game	+ 28	- 28
After	1 u	1 u	1 u

(a)
Number of beads that Xuan won from Betty
= ¹₄ x 56
= 14

Number of beads that Xuan lost to Pamela
= ⁶₇ x 56
= 48

Number of beads that Xuan won from Betty
= ¹₂ x 56
= 28

Number of beads that Xuan had in the end
= 56 + 14 - 48 + 28
= 50

(b)
Number of beads that Betty had at first
= 1 u + 28 + 48 + 14
= 50 + 28 + 48 + 14
= 140 

Answer(s): (a) 50 ; (b) 140