Sabrina, Dana and Winnie were playing with beads. Sabrina started with 72 beads and in the first game, she won ²₃ more beads from Dana. In the second game, Sabrina lost ⁵₈ of her original number of beads to Winnie. Dana lost as many beads as Sabrina to Winnie. In the final game, Sabrina won ¹₂ of her original number of beads from Dana. All of them ended up with the same number of beads.

1. How many beads did Sabrina have in the end?
2. How many beads did Dana have at first?

	Sabrina	Dana	Winnie
Before	72
First game	+ 48	- 48
Second game	- 45		+ 45
		- 45	+ 45
Final game	+ 36	- 36
After	1 u	1 u	1 u

(a)
Number of beads that Sabrina won from Dana
= ²₃ x 72
= 48

Number of beads that Sabrina lost to Winnie
= ⁵₈ x 72
= 45

Number of beads that Sabrina won from Dana
= ¹₂ x 72
= 36

Number of beads that Sabrina had in the end
= 72 + 48 - 45 + 36
= 111

(b)
Number of beads that Dana had at first
= 1 u + 36 + 45 + 48
= 111 + 36 + 45 + 48
= 240 

Answer(s): (a) 111 ; (b) 240