Nora, Hilda and Jane were playing with beads. Nora started with 40 beads and in the first game, she won
35 more beads from Hilda. In the second game, Nora lost
18 of her original number of beads to Jane. Hilda lost as many beads as Nora to Jane. In the final game, Nora won
15 of her original number of beads from Hilda. All of them ended up with the same number of beads.
- How many beads did Nora have in the end?
- How many beads did Hilda have at first?
|
Nora |
Hilda |
Jane |
Before |
40 |
|
|
First game |
+ 24 |
- 24 |
|
Second game |
- 5 |
|
+ 5 |
|
|
- 5 |
+ 5 |
Final game |
+ 8 |
- 8 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Nora won from Hilda
=
35 x 40
= 24
Number of beads that Nora lost to Jane
=
18 x 40
= 5
Number of beads that Nora won from Hilda
=
15 x 40
= 8
Number of beads that Nora had in the end
= 40 + 24 - 5 + 8
= 67
(b)
Number of beads that Hilda had at first
= 1 u + 8 + 5 + 24
= 67 + 8 + 5 + 24
= 104
Answer(s): (a) 67 ; (b) 104