Nora, Lynn and Anna were playing with beads. Nora started with 84 beads and in the first game, she won
34 more beads from Lynn. In the second game, Nora lost
47 of her original number of beads to Anna. Lynn lost as many beads as Nora to Anna. In the final game, Nora won
13 of her original number of beads from Lynn. All of them ended up with the same number of beads.
- How many beads did Nora have in the end?
- How many beads did Lynn have at first?
|
Nora |
Lynn |
Anna |
Before |
84 |
|
|
First game |
+ 63 |
- 63 |
|
Second game |
- 48 |
|
+ 48 |
|
|
- 48 |
+ 48 |
Final game |
+ 28 |
- 28 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Nora won from Lynn
=
34 x 84
= 63
Number of beads that Nora lost to Anna
=
47 x 84
= 48
Number of beads that Nora won from Lynn
=
13 x 84
= 28
Number of beads that Nora had in the end
= 84 + 63 - 48 + 28
= 127
(b)
Number of beads that Lynn had at first
= 1 u + 28 + 48 + 63
= 127 + 28 + 48 + 63
= 266
Answer(s): (a) 127 ; (b) 266