Marion, Lynn and Hilda were playing with beads. Marion started with 28 beads and in the first game, she won ³₄ more beads from Lynn. In the second game, Marion lost ³₇ of her original number of beads to Hilda. Lynn lost as many beads as Marion to Hilda. In the final game, Marion won ¹₂ of her original number of beads from Lynn. All of them ended up with the same number of beads.

1. How many beads did Marion have in the end?
2. How many beads did Lynn have at first?

	Marion	Lynn	Hilda
Before	28
First game	+ 21	- 21
Second game	- 12		+ 12
		- 12	+ 12
Final game	+ 14	- 14
After	1 u	1 u	1 u

(a)
Number of beads that Marion won from Lynn
= ³₄ x 28
= 21

Number of beads that Marion lost to Hilda
= ³₇ x 28
= 12

Number of beads that Marion won from Lynn
= ¹₂ x 28
= 14

Number of beads that Marion had in the end
= 28 + 21 - 12 + 14
= 51

(b)
Number of beads that Lynn had at first
= 1 u + 14 + 12 + 21
= 51 + 14 + 12 + 21
= 98 

Answer(s): (a) 51 ; (b) 98